Arrange the following bonds in order of incre | vedclass

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(A) The ionic character of a covalent bond depends on the difference in electronegativity between the bonded atoms. Greater the electronegativity diff

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$C-C < C-N < C-O$

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(A) The ionic character of a covalent bond depends on the difference in electronegativity between the bonded atoms. Greater the electronegativity difference,higher is the ionic character. The electronegativity values on the Pauling scale are: $C = 2.5, N = 3.0, O = 3.5$. $1$. For $C-C$: Electronegativity difference = $|2.5 - 2.5| = 0$. $2$. For $C-N$: Electronegativity difference = $|3.0 - 2.5| = 0.5$. $3$. For $C-O$: Electronegativity difference = $|3.5 - 2.5| = 1.0$. Since the electronegativity difference follows the order $0 < 0.5 < 1.0$,the order of increasing ionic character is $C-C < C-N < C-O$.

Arrange the following bonds in order of increasing ionic character: $C-O, C-N$ and $C-C$. Give reasons.

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